Twelve balls can be distributed in 3 box.Probabilty of 1st box having 3 ball
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Total # of ways to distribute 12 balls in 3 boxes is 3^12
Total # of ways in which 1st box contains exactly 3 balls is (12C3)*(2^9)
Required probability is ((12C3)*(2^9))/3^12
Total # of ways in which 1st box contains exactly 3 balls is (12C3)*(2^9)
Required probability is ((12C3)*(2^9))/3^12
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