Twelve friends go out for dinner to a restaurant, where they find 2 circular tables one with 7 chairs and other with5 chairs. In how many ways can the group settle down ?
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Any 4 friends can be selected from 9 friends in 9C4 ways = 126 ways -----> 1
The remaining 5 friends can be selected from 5 in 5C5 = 1 way ------> 2
now the 4 friends can be seated around the circular table in (4-1)! ways
=> 6 ways ----------> 3
and the remaining 5 friends can be arranged/seated around the circular table in (5-1)! ways = 24 ways.
so the total number of ways in which 9 friends sit around 2 circular tables that can seat 4 and 5 respectively can be got by multiplying 1, 2, 3 and 4 above to get 126 * 1 * 6 * 24 = 18144 ways.
i was not able to solve ur question
this is an exemplar answer
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The remaining 5 friends can be selected from 5 in 5C5 = 1 way ------> 2
now the 4 friends can be seated around the circular table in (4-1)! ways
=> 6 ways ----------> 3
and the remaining 5 friends can be arranged/seated around the circular table in (5-1)! ways = 24 ways.
so the total number of ways in which 9 friends sit around 2 circular tables that can seat 4 and 5 respectively can be got by multiplying 1, 2, 3 and 4 above to get 126 * 1 * 6 * 24 = 18144 ways.
i was not able to solve ur question
this is an exemplar answer
sorry
pls mark as brainnliest
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