Question

Twelve identical resistance R each form a cube as shown in the figure. Resistance across its face diagonal AB corners is

Answer 1

Explanation:

Twelve wire, each having resistance r, are joined to form a cube as shown in figure. Find the equivalent resistance between the end of a face diagonal such as aandc. ... The current distribution is shown in figure. ltbygtBy symmetry, the paths ad and ab are equivalent and hence will carry the same current i1.

Answer 2

Answer:

5R/6

Explanation:

This circuit cannot be solved by considering series and parallel connections.

This circuit cannot be solved by considering series and parallel connections.All three paths from A to B are identical. Let 3I current entered at end A and left at end B. Current is distributed in all branches using symmetry.

This circuit cannot be solved by considering series and parallel connections.All three paths from A to B are identical. Let 3I current entered at end A and left at end B. Current is distributed in all branches using symmetry.If Va - Vb = V, then Rab = V/3I .....(i)

This circuit cannot be solved by considering series and parallel connections.All three paths from A to B are identical. Let 3I current entered at end A and left at end B. Current is distributed in all branches using symmetry.If Va - Vb = V, then Rab = V/3I .....(i)We have,

This circuit cannot be solved by considering series and parallel connections.All three paths from A to B are identical. Let 3I current entered at end A and left at end B. Current is distributed in all branches using symmetry.If Va - Vb = V, then Rab = V/3I .....(i)We have, Va - Vb = (Va - Vp) + ((Vp - Vq) + (Vq - Vb)

This circuit cannot be solved by considering series and parallel connections.All three paths from A to B are identical. Let 3I current entered at end A and left at end B. Current is distributed in all branches using symmetry.If Va - Vb = V, then Rab = V/3I .....(i)We have, Va - Vb = (Va - Vp) + ((Vp - Vq) + (Vq - Vb)=> V = IR + I/2R + IR

This circuit cannot be solved by considering series and parallel connections.All three paths from A to B are identical. Let 3I current entered at end A and left at end B. Current is distributed in all branches using symmetry.If Va - Vb = V, then Rab = V/3I .....(i)We have, Va - Vb = (Va - Vp) + ((Vp - Vq) + (Vq - Vb)=> V = IR + I/2R + IR=> V = 5IR/2

This circuit cannot be solved by considering series and parallel connections.All three paths from A to B are identical. Let 3I current entered at end A and left at end B. Current is distributed in all branches using symmetry.If Va - Vb = V, then Rab = V/3I .....(i)We have, Va - Vb = (Va - Vp) + ((Vp - Vq) + (Vq - Vb)=> V = IR + I/2R + IR=> V = 5IR/2=> V/I = 5R/2

This circuit cannot be solved by considering series and parallel connections.All three paths from A to B are identical. Let 3I current entered at end A and left at end B. Current is distributed in all branches using symmetry.If Va - Vb = V, then Rab = V/3I .....(i)We have, Va - Vb = (Va - Vp) + ((Vp - Vq) + (Vq - Vb)=> V = IR + I/2R + IR=> V = 5IR/2=> V/I = 5R/2=> Rab = V/3I = 5R/6

ANSWER : 5R/6