Question

Twelve men can complete a work in 8 days. Three days after they started the work, 3 more men joined them. In how many days will all of them together complete the remaining work ?

Answer 1

=>12 ×3 = 15 × 5
=>X = 12/25

Answer 2

Answer:

4 days.

Step-by-step explanation:

Twelve men can complete a work in 8 days.

12 men 1 day work = $\frac{1}{8}$

12 men 3 days work = $\frac{3}{8}$

Remaining work = $1-\frac{3}{8}=\frac{5}{8}$

After 3 days 3 more men joined them.

1 men 1 day work = $\frac{1}{8 \times 12}$

15 men 1 day work = $\frac{1}{8 \times 12} \times 15$

                              = $\frac{5}{32}$

So, 15 men complete  $\frac{5}{32}$ part of work in days = 1

15 men complete whole work in days = $\frac{1}{\frac{5}{32}}$

15 men complete$\frac{5}{8}$ part of work in days = $\frac{1}{\frac{5}{32}} \times \frac{5}{8}$

                                                                                              = $4$

So, they altogether complete remaining work in 4 days.