Question

Twelve years ago, John was 18 years more than twice his daughter's age. After how many years from now his daughter's age?
8 16 12, cannot be determined​

Answer 1

let John's daughter age be x and and 2x+18

if x=8 then 2x+18 =2(8)+18=34

if x=16 then 2x+18= 2(16)+18 =50

if x=12 then 2x+18 = 2(12)+18= 42

Answer 2

Given:

Twelve years ago, John was 18 years more than twice his daughter's age.

To find:

After how many years from now is his daughter's age?

Step-by-step explanation:

• We will solve the question by simply assuming the age of John and his daughter to be of some variable.

Solution:

Let John's age $=x$

Let his daughter's age $=y$

Now, twelve years ago

$x-12 = 18 + 2y\\\\x-2y = 18 +12\\\\x-2y = 30$

If  the values of $x = 8,16,12$

$y = 18 + 2(8)\\\\=18+16\\\\=34\\\\y = 18+ 2(16)\\\\= 18 +32\\\\=50\\\\y = 18+2(12)\\\\=18+24\\\\=42$

Hence, $34,50,42$ are the values of his daughter's age.