Question

Twelve years ago, the age of X was 2.5 times that of
Y. The sum of the present ages of X and Y is
108 years. Find the age difference between X and Y.​

Answer 1

Answer:

The age difference is 36.

Step-by-step explanation:

Let the age of Y 12 years ago be A.

Then age of X 12 years ago is 2.5A.

Note that present age is the age after 12 years have passed.

Hence present age of Y= A+12

and that of X=2.5A +12.

Since sum of present ages is 108,

2.5A+12 + A +12= 108.

Solving,

3.5A +24=108

3.5A=84.

A=24.

Age difference=(2.5×24+12)-(24+12)=36.