Question

Twenty caravans are travelling across the desert one day apart. The first caravan reaches the oasis and the camel drank half of the water in the pool. On the second day, the second caravan reaches the oasis and the camel drank one third of the water that was left. On the third day the camel bin the third caravan drank one quarter of the water that was left. On the first day the pool contained 1050 sq.metre of water. How much water was left after the twenty caravan passed through.

Answer 1

Answer:

The first caravan left half of the water. The second caravan left  

\frac{2}{3}  \times  \frac{1}{2}  =  \frac{1}{3}  \\  \frac{3}{4}  \times  \frac{1}{3}  =  \frac{1}{4}  

of the water. Continuing the pattern, the 20th caravan leaves  

\frac{1}{21}  

or 50 m3 of water.

Step-by-step explanation:

Answer 2

50 m³ of water was left after the twenty caravan passed through.

Given,

Twenty caravans are travelling across the desert one day apart. The first caravan reaches the oasis and the camel drank half of the water in the pool. On the second day, the second caravan reaches the oasis and the camel drank one third of the water that was left. On the third day the camel bin the third caravan drank one quarter of the water that was left. On the first day the pool contained 1050 sq.metre of water.

To find,

How much water was left after the twenty caravan passed through?

Solution,

The first caravan left half of the water.

The second caravan left  one third of water

$\frac{2}{3}$  x  $\frac{1}{2}$  =  $\frac{1}{3}$  

The third caravan left one fourth of water

$\frac{3}{4}$  x  $\frac{1}{3}$  =  $\frac{1}{4}$

Continuing the pattern, the 20th caravan leaves  $\frac{1}{21}$ of the water.

⇒  $\frac{1}{21}$ of 1050 = 50 m³ of water.

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