Twenty four is divided into two parts such that 7 times the first part added to 5 times the second part makes 146. Find each part.
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let first part be (x) and second(y)
x+y=24(y=24-x)
7x+5y=146
7x+5(24-x)=146
7x+120-5x=146
2x=146-120
2x=26
x=13
y=24-x
y=24-13
y=11
therefore:x=13 and y=11
x+y=24(y=24-x)
7x+5y=146
7x+5(24-x)=146
7x+120-5x=146
2x=146-120
2x=26
x=13
y=24-x
y=24-13
y=11
therefore:x=13 and y=11
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