Math, asked by dsravankumar2007, 8 months ago

Twenty recruits stand in a long column, one behind the other. At a signal from the sergeant, the recruits standing in places 10 and 20 step forward into places 1 and 2 respectively and the others steps back. Find the least number of these maneuvers that must occur before the recruit originally in place 1 will be in place 1 once again.

Answers

Answered by amitnrw
1

Given : Twenty recruits stand in a long column, one behind the other. At a signal from the sergeant, the recruits standing in places 10 and 20 step forward into places 1 and 2 respectively and the others steps back.

To Find : the least number of these maneuvers that must occur before the recruit originally in place 1 will be in place 1 once again.

Solution:

A is at 1

After 1st change

A will be at 3rd

After 2nd change

A will be at 5th

After 3rd change

A will be at 7th

After 4th change

A will be at 9th

After 5th change

A will be at 11th

After that on each change A' position will be changed by 1

as position 10th is already  ahead of  him

9 more changes makes A  at 20

After 14th change A will be at 20th

in 15th change A will be back to origin position

15 is the  least number of these maneuvers that must occur before the recruit originally in place 1 will be in place 1 once again.

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