Twenty seven solid iron spheres ,each of radius 2cm are melted to form a new solid sphere. what will be the surface area of the new sphere
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volume of small spheres=volume of big sphere
24(4/3×3.14×8)=4/3×3.14×r^3
24×33.493=4.186×r^3
r^3=24×33.493/4.186
r^3=803.832/4.186
r=cube root of (192.028)
r=5.769cm
TSA of sphere=4×3.14×5.769
=72.45864cm^2
24(4/3×3.14×8)=4/3×3.14×r^3
24×33.493=4.186×r^3
r^3=24×33.493/4.186
r^3=803.832/4.186
r=cube root of (192.028)
r=5.769cm
TSA of sphere=4×3.14×5.769
=72.45864cm^2
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