. Twenty seven solid iron spheres, each of radius r and surface area S are melted to
form a sphere with surface area S. Find the
@ radius r' of the new sphere, (ii) ratio of S and S'.
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Answer:
Answer
(i) Radius of 1 solid iron sphere =r
⇒Volume =
3
4
πr
3
⇒Volume of 27 solid iron spheres =27×
3
4
πr
3
⇒
3
4
πr
′
3
=27×
3
4
πr
3
r
′
3
=2πr
3
⇒r
′
=3r
(ii) Surface area =4πr
2
SA r
′
=4πr
′
2
=4π(3r)
2
=36πr
2
S
′
S
=
36πr
2
4πr
2
=
9
1
=1:9
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