Math, asked by vrajkaurjustmeh, 6 months ago

Twenty seven solid iron spheres, each of radius r and surface area S are

melted to form a sphere with surface area S′. Find the

(i) radius r ′ of the new sphere,

(ii) ratio of S and S′.​

Answers

Answered by rajarayanshahzad7984
6

Answer:

if p(m = M3+ 2m²-m+

10+2m²-mt 10 then

cas + p(-a)=2

Answered by Anonymous
26

 \large \pink{Question:-}

Twenty seven solid iron sphere , each of radius "r" and surface area "s" are melted to form a sphere with surface area "s" find the ....

➊ radius r' of the new sphere ,

\large\blue{Answer:- }

  \red\rightarrow27 \times  \frac{4}{3} \times \pi \times r^{2} =  \frac{4}{3} \times \pi \times r^{2}

  \pink\rightarrow3 \sqrt{27r^{3} } = r ^{3}

  \orange\rightarrow3r \:  = r......(1)

➋ ratio of S and S' .

 \large\red{Answer:- }

 \blue  \rightarrow\frac{sa1}{sa2} =  \frac{4\pi \: r^{2} }{4\pi \: r^{2} }  =   \frac{4\pi \: r^{2} }{4\pi \times (3r)^{2} }

 \green \rightarrow \:  \frac{r}{9r^{2} } =  \: 1 : 9 \:  \:  \:

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