Question

Twenty seven years ago, a man's age was half his wife's present age. sum of their present ages is 90 years. what are the respective present ages of the man and his wife?

Answer 1

I think it would help you

Answer 2

$\underline{ \blue { At \: present :}}$

$Age \:of \:a \: Man = x \: years$

$Age \:of \: a\: Woman = ( 90 - x )\: years$

$\underline{ \blue { Twenty \: seven \: years \: ago:}}$

$Age \:of \:a \: Man = (x - 27) \: years$

/* According to the problem given */

$x - 27= \frac{1}{2} ( 90-x)$

$\implies 2(x-27) = 90 - x$

$\implies 2x - 54 = 90 - x$

$\implies 2x + x = 90 + 54$

$\implies 3x = 144$

$\implies x = \frac{144}{3}$

$\implies x = 48$

$\underline{ \blue { At \: present :}}$

$Age \:of \:the \: Man = x = 48\: years$

$Age \:of \: the\: Woman = ( 90 - 48 )\: years\\= 42\:years$

•••♪