Twenty years ago a father was five times as old as his son and 4 years hence he will be twice as old as his son. Find their present age.
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Step-by-step explanation:
let present age of father =F, Son =S
F-20 = 5(S-20)
F-20 = 5S - 100
F = 5S-80
F+4 = 2(S+4)
5S - 80 +4 = 2S + 8
3S = 80-4+8 =84
S = 84/3 = 28
F = 5×28 -80 = 60
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