Math, asked by gaichamdinr5, 4 months ago

Twenty years ago a father was five times as old as his son and 4 years hence he will be twice as old as his son. Find their present age.

Answers

Answered by bson
3

Step-by-step explanation:

let present age of father =F, Son =S

F-20 = 5(S-20)

F-20 = 5S - 100

F = 5S-80

F+4 = 2(S+4)

5S - 80 +4 = 2S + 8

3S = 80-4+8 =84

S = 84/3 = 28

F = 5×28 -80 = 60

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