Question

Twenty years ago the age of father was four times the age of his son . After four years from now the age of father will be double that of his son . Give algebraic and graphical representation of this situation ... (please give full explanation of answer with graph also....!!!!)​

Answer 1

Answer:

Step-by-step explanation:

let sons age now be x

20 years ago son's age = x-20

fathers age = 4(x-20)

4 years hence

sons age = x+4

fathers age = 4(x-20)+24

4(x-20)+24= 2(x+4)

4x-80+24=2x+8

4x-56=2x+8

4x-2x=56+8

2x=64

x=32 son's age now

20 years ago father's age = 4(x-20)=>4(32-20)=>48

So now father is 68 years

Answer 2

Answer:

Hey

the answer is attached in the pic

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