Question

twice a number addedd with thrice a another number give 23.four times the first number five times the second number when give 41. ​

Answer 1

Answer:

let x and y are required numbers

2x+3y = 23. (1)

4x+5y = 41. (2)

by solving 1 and 2

x = 4 and y = 5

one is 4 and other is 5