Question

Twice a number decreased by $13.7$ is greater than $125.28$. What is the smallest integer that satisfies this condition?

Answer 1

Answer:

Let a no. be x.

2x - 13.7 = 125.28

x - 13.7= 125.8/2

x-13.7 =62.4

x= 62.4 + 13.7

x= 76.1 answer.

Answer 2

The smallest integer that satisfies this condition is 70.

Step-by-step explanation:

Given : Twice a number decreased by $13.7$ is greater than $125.28$.

To find : What is the smallest integer that satisfies this condition?

Solution :

Let the number be 'x'.

Twice a number decreased by $13.7 i.e. '2x-13.7'.

Twice a number decreased by $13.7$ is greater than $125.28$.

i.e. $2x-13.7 > 125.28$

Add 13.7 both side,

$2x-13.7+13.7 > 125.28+13.7$

$2x > 138.98$

Divide both side by 2,

$\frac{2x}{2} >\frac{138.98}{2}$

$x>69.49$

The smallest integer that satisfies this condition is x=70.

#Learn more

If original number is x ,then what is twice GREATER than the original number ? (NOT TWICE OF THE NUMBER ,TWICE GREATER )​

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