Question

Twice a number decreased by 22 is 48 .Find the number.

Answer 1

Answer:

Let the no be x

A/C

2x-22 =48

2x=48+22

2x = 70

x = 70÷2

x = 35

Therfore, the no is 35

Hope it helps

Answer 2

Answer:

35

Step-by-step explanation:

Given,

Twice a number decreased by 22 is 48

To Find :-

The number

Solution :-

Let,

the required number be 'x'.

According to question :-

Twice a number =  $\sf 2\times x = 2x$

Twice a number decreased by 22 = 2x - 22

$\sf\implies$ 2x - 22 = 48

Transposing 22 to R.H.S :-

2x = 48 + 22

2x = 70

x = 70/2

x = 35

Therefore , required number = x = 35