Question

Twice A number decreased by 7 Gives 45Find the number.​

Answer 1

Answer :-

• 26 is the required number.

Given :-

• Twice a number decreased by 7 gives 45.

To find :-

• The number.

Step-by-step explanation :-

Detailed explanation of the solution :-

Let's understand!

In this question, it is said that twice a number decreased by 7 gives 45. We have to find that number. So, we will construct an equation using the given information and use it to find out the answer.

Calculations :-

Let's assume that the number is x.

Then twice the number will be 2x.

Now, it is said that when twice the number is decreased by 7, the result is 45.

So, we have to decrease 7 from the expression obtained. We get 2x - 7.

The result is 45, so this expression must be equal to 45.

Therefore, we get :-

$\bf2x - 7 = 45$

Transposing 7 from LHS to RHS, changing it's sign from (-) to (+).

$\bf2x = 45 + 7$

Adding the numbers,

$\bf2x = 52$

Transposing 2 from LHS to RHS, changing it's sign from (×) to (÷).

$\bf x = \dfrac{52}{2}$

Dividing 52 by 2,

$\bf x = 26.$

The value of x is 26.

So, twice the number decreased by 7 which gives 45 is 26.

Answer 2

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

Question:

Twice a number decreased by 7 Gives 45. Find the number.

Concept:

Here in this given query , first of all we will assume the number as ' x ' and we will make it twice which will be ' 2x ' . Now , according to the query we will minus ' 2x ' with ' 7 ' which will give ' 45 ' which means ' 2x - 7 = 45 ' . By this equation we will get the required answer

.

Solution:

Let the number number be x

When the number is twice it will be 2x

Now,

According to the question,

➟ 2x - 7 = 45

➟ 2x = 45 + 7

➟ 2x = 52

➟ x = 52/2

➟ x = 26

Therefore, 26 is the required number and the value of x.

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯