Question

Twice a number decreased by 8 is 2 less than half the number. What is the number? 4

Answer 1

Answer:

equation is 2x-8=x/2-2

Answer 2

$\huge{\bold{\underline{\underline{Question:-}}}}$

Twice a number decreased by 8 is 2 less than half the number. What is the number?

$\huge{\bold{\underline{\underline{Solution:-}}}}$

Let's assume the number to be 'x'

A.T.Q.

$= > 2x - 8 = 2 - \frac{1}{2}x$

$= > 2x - 8 = \frac{(4 - x)}{2}$

$= > 2x - 8 = 2 - \frac{x}{2}$

$= > 2x - 8 = \frac{(2 \times 2) - x}{2}$

$= > 2(2x - 8) = (4 - x)$

$= > 4x - 8 = 4 - x$

$= > 4x + x = 4 + 8$

$= > 5x = 12$

$= > x = \frac{12}{5}$

So, the number is $\dfrac{12}{5}$