Twice a number,n, subtracted form 36 is less than 15 more than one third the number. Find all possible values for the number
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Twice (2 x ) a number (n), subtracted (-) from 36, is less than (<) 15 more than (+) one-third (1/3) the number (n).
36 - 2n < 15 + 1/3n Subtract 15 from both sides
21 - 2n < 1/3n Add 2n to both sides
21 < 7/3n Multiply both sides by 3/7 to cancel out the fraction
63/7 < n Simplify the fraction
9 < n Switch the sides to make it easier to read
n > 9
The possible values for the number are anything over 9
-Ekansh Nimbalkar
36 - 2n < 15 + 1/3n Subtract 15 from both sides
21 - 2n < 1/3n Add 2n to both sides
21 < 7/3n Multiply both sides by 3/7 to cancel out the fraction
63/7 < n Simplify the fraction
9 < n Switch the sides to make it easier to read
n > 9
The possible values for the number are anything over 9
-Ekansh Nimbalkar
Answered by
0
This equation will come...
36-2n=1/3n +15
36-15=1/3n +2n
32=7n/3
n=9
Answer=9
36-2n=1/3n +15
36-15=1/3n +2n
32=7n/3
n=9
Answer=9
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