Question

Twice a number subtracted 19is 11

Answer 1

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Answer 2

The value is 15.

Step-by-step explanation:

Let the number be 'x'

Twice a number is expressed as

$2x$

Subtracted 19 from it is expressed as

$2x-19$

It is equal to 11

According to question, it becomes,

$2x-19=11\\\\2x=11+19\\\\2x=30\\\\x=\dfrac{30}{2}\\\\x=15$

Hence, the value is 15.

# learn more:

Express $\dfrac{30+19i}{4+9i}$ in the form $a + bi$, where $a$ and $b$ are real numbers.

https://brainly.in/question/1217168