Math, asked by tumungsaritagmailcom, 8 months ago

Twice a number when decreased by 7 gives 45. Find the number​

Answers

Answered by rishabh112005patel
1

Step-by-step explanation:

Let the number be X

ATQ

2x-7=45

2x=45-7

2x=38

x=16

Answered by chotukumar8987
0

Step-by-step explanation:

Let the number be x.

twice =2x

When it is decreased by 7 we get the following equation:

2x−7=45

⇒2x=45+7

⇒2x=52

⇒x=

2

52

∴x=26

The number is 26.

Similar questions