Question

Twice a number when decreased by 7 gives 45. Find the number.​

Answer 1

Given:

• Twice a number when decreased by 7 gives 45.

Need To Find:

• The required number ?

Solution:

Let the number be "x".

Then, Twice of the number will be 2x.

According to the question,

➜ 2x - 7 = 45

➜ 2x = 45 + 7

➜ 2x = 52

➜ x = 52/2

➜ x= 26

Hence, the required number is 26.

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Answer 2

Answer:

Given :-

• Twice a number when decreased by 7 gives 45.

To Find :-

• What is the number.

Solution :-

Let, the number be x

If, the number will be twice then the number will be 2x

According to the question,

⇒ 2x - 7 = 45

⇒ 2x = 45 + 7

⇒ 2x = 52

⇒ x = 52/2

➠ x = 26

Hence, the required number is 26.

∴ The number is 26 .

Let's Verify :-

↦ 2x - 7 = 45

Put x = 26 we get,

↦ 2(26) - 7 = 45

↦ 52 - 7 = 45

↦ 45 = 45

➦ LHS = RHS

Hence, Verified ✔