Twice a number x added to the square of a number y all divided by the product of two numbers v and z.
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Answer:
2x+y²/vz
Step-by-step explanation:
twice a no.x = 2x
square of no.y = y²
according to to question 2x and y² are added to each other = 2x + y²
Then they are divided by product of two no. v and z.
product of v and z is = vz
Then finally, we will divide 2x + y² by vz
so, 2x + y²/vz
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