Twice the complement of an angle is 35° less than the supplement of the angle. Find the angle.
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angle=x
complemnent=90-x
supplement=180-x
2(x-90)=(180-x)-35
2x-180=180-x-35
3x=345
x=115
complemnent=90-x
supplement=180-x
2(x-90)=(180-x)-35
2x-180=180-x-35
3x=345
x=115
Answered by
0
Let the angle be x.
Now, complement=90-x
supplement= 180-x
Now, as per the question
2(90-x)+35=180-x
180-2x+35=180-x
35=2x-x [180 gets cancelled]
x=35
Therefore the required angle is 35°.
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