Question

Twice the greater of two consecutive odd integers is 13 less than three times the lesser, how do you find the integers?

Answer 1

As the two numbers are consecutive odd integers, let them be x and x + 2.

Given that twice the greater among them is 13 less than thrice the smaller.

This can be written mathematically as,

2(x + 2) = 3x - 13

=> 2x + 4 = 3x - 13

=> 13 + 4 = 3x - 2x

=> 17 = x

=> 17 = x=> 19 = x + 2

Hence the numbers are 17 and 19.

Let's check.

19 × 2 = 38

17 × 3 - 13 = 51 - 13 = 38

Checked!!! ✓✓✓