Twice the length of a rectangle is three times the width. The perimeter is 320 cm.find the dimensions of the rectangle
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2l=3b
=> l=3b/2------(1)
Now,
2(l+b)=320
=> 2(3b/2+ b)=320
=> 3b + 2b= 320
=> 5b=320
=> b=320/5
=>b=64cm
.-. (1)=>l=(3×64)/2
=3×32
=96cm
2l=3b
=> l=3b/2------(1)
Now,
2(l+b)=320
=> 2(3b/2+ b)=320
=> 3b + 2b= 320
=> 5b=320
=> b=320/5
=>b=64cm
.-. (1)=>l=(3×64)/2
=3×32
=96cm
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