Question

Twice the length of a rectangle is three times the width. The perimeter is 320cm. find the dimensions of the rectangle.

Answer 1

Answer:

let the width be x and length be y

2y=3x

y=3x/2

perimeter= 2(l+b)

                2(x+3x/2) = 320

               2(5x/2) = 320

               5x/2 = 160

              x= 160*2/5

              x= 64m

            y= 3*64/2  = 96m

therefore length is 96m and breadth is 64m

Step-by-step explanation:

Answer 2

Let the length of the rectangle be a cm and the width of the rectangle be b cm,


According to the question: Twice the length of a rectangle is three times the width.

So,
= > 2 x Length of rectangle = 3 x width of the rectangle

= > 2 x a = 3 x b

= > 2a = 3b ----: ( 1 )


====================
From the properties of rectangle, we know : -
Perimeter of rectangle = 2( length + breadth )
====================

Hence,
= > 2( a + b ) = 320

= > 2a + 2b = 320


From above, 2a = 3b,

= > 3b + 2b = 320

= > 5b = 320

= > b = 320 / 5

= > b = 64



Now, substituting the value of b in ( 1 ),

= > 2a = 3b

= > 2a = 3 x 64

= > a = 3 x 64 / 2

= > a = 96




Hence,
length of the rectangle is 96 cm and breadth of the rectangle is 64 cm.
$\:$