Question

Twice the number decreased by 22 is 48 . Find the number

Plz help

Answer 1

Let the number be x
Twice it - 2x
Decrease22- 2x-22
According to this
2x-22=48
2x=20
x=35

Answer 2

Given,

Twice the number decreased by 22 is 48.

To find,

The value of the number.

Solution,

Let the number that is to be x.

Twice the number decreased by 22 is 48. We can interpret this statement mathematically as-

⇒  2x -22 = 48.

We know that -22 will shift from Left Hand Side of the equation to Right Hand Side and its sign would change from -22 to +22. So, we are left with the equation as below:

⇒   2x = 48 +22

⇒   2x = 70

⇒   x = 35

Hence, the value of the number x that is to be found is 35.