Question

twice the number when decreased by 7 given 45.find the number.​

Answer 1

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Let the required number be x.

Then, = 2x – 7 = 45

Transposing -7 to RHS and it becomes 7.

= 2x = 45 + 7

= 2x = 52

Multiplying both side by (1/2) = 2x × (1/2) = 52 × (1/2) =

x = 26

∴ The required number is 26.

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Answer 2

Answer:

let the number be 'x'

A.T.Q

2x - 7 = 45

2x = 45+7

2x = 52

x = 52/ 2

x = 26 ANS

hope it helps u