Question

Twice the product of zeroes of the polynomial 23^x-26x+161 is 14p find p

Answer 1

SOLUTION

GIVEN

Twice the product of zeroes of the polynomial 23x² - 26x + 161 is 14p

TO DETERMINE

The value of p

EVALUATION

Here the given polynomial is

23x² - 26x + 161

Comparing with the general polynomial

ax² + bx + c we get

a = 23 , b = - 26 , c = 161

Product of the Zeros

= c/a

= 161/23

= 7

So by the given condition

2 × 7 = 14p

⇒ 14 = 14p

⇒ 14p = 14

⇒ p = 1

FINAL ANSWER

Hence the required value of p = 1

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ Form a quadratic equation such that one of its roots is 5. Forma quadratic equation for it and write.

https://brainly.in/question/38226428

2. If p = 1 and q = –2 are roots of a quadratic equation, then quadratic equation will be

https://brainly.in/question/39283719