Question

twice the smaller of 2 consecutive odd integers is 7 more than the larger. what are the integers?

Answer 1

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Here is the solution:

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Let the smaller number be x

The other number is (x + 2)

Form the equation:

2x -7 =  x + 2

x = 9

Find the numbers:

smaller number = x = 9

larger number = x + 2 = 11

Answer: The two numbers are 9 and 11

Answer 2

Hope u like my process
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=> Let the smaller integer be x

=> Larger integer = (x +2)

By problems
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$= > 2x - (x + 2) = 7 \\ \\ = > \blue{2x - x - 2} = \blue{7 } \\ \\ = > \boxed{ x = \blue{7 +2} = \bf \underline{\green{9} }}$

The larger integer is (x+2) = 9+2 = 11

The smallest integer = 9

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