Math, asked by diyajaindivya, 1 year ago

Twice the son's age in years, is added to the father's age, the sum is 70. But, if twice the father's age added to the son's age, the sum is 95. Find their ages. Answer using 1 variable( i.e. 'x' ) only.


Class 8​

Answers

Answered by navdeepsatyam2006
4

Step-by-step explanation:

let the the son's age be x

And their father's age be 2x

2x + x :- 70

3x :- 70

x :- 70/3

Answered by Anonymous
11

• Let present age of father be (x) years and present age of son be (y) years.

» Twice the son's age in years, is added to the father's age, the sum is 70.

A.T.Q.

⇒ x + 2y = 70

⇒ x = 70 - 2y _________ (eq 1)

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» Twice the father's age added to the son's age then the sum is 95.

A.T.Q.

⇒ 2x + y = 95

⇒ 2(70 - 2y) + y = 95

⇒ 140 - 4y + y = 95

⇒ - 3y = 95 - 140

⇒ - y = - 45/3

⇒ y = 15 (age of son)

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Put value of y in (eq 1)

⇒ x = 70 - 2(15)

⇒ x = 70 - 30

⇒ x = 40 (age of father)

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Present age of father = 40 years

Present age of son = 15 years.

_________ [ ANSWER ]

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✡ VERIFICATION :

From above calculations we have x = 40 and y = 15

Put value of x and y in this equation : x + 2y = 70

→ 40 + 2(15) = 70

→ 40 + 30 = 70

→ 70 = 70

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