Question

twice the square of the sum of a number and 3 is 98. Find the number​

Answer 1

Answer:

x=4 or -10

Step-by-step explanation:

Let the number be x.

given,2(x+3)^2=98

or,2(x^2+6x+9)=98

or,x^2+6x+9=49

or,x^2+6x-40=0

or,x^2+10x-4x-40=0

or,x(x+10)-4(x+10)=0

or,x=4,-10