Twice the square of the sum of a number and 3 is 98. Find the number?
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Answered by
22
Answer:
let the number be x
2(x+3)^2 = 98
(x+3)^2 =98/2
(x+3)^2 = 49
x+3=√49
x+3=7
x=7-3
x=4
Answered by
1
Given : Twice the square of the sum of a number and 3 is 98.
To Find: the number
Solution:
Let say number is N
Then 2 (N + 3)² = 98
=> (N + 3)² = 49
=> N + 3 = ± 7
=> N + 3 = 7 or N + 3 = - 7
=> N = 4 or N = - 10
Hence the number is
4 or - 10
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