Question

Twice the sum of the first and third of three consecutive integersis 80 more than the second integer

Answer 1

Answer:

26,27,28.

Step-by-step explanation:

Let the three consecutive numbers be x , x+1 , x+2.

given that, twice the sum of first and third numbers is 80 more than the second number.

2(x + x + 2) = x + 1 + 80

2(2x + 2) = x + 82

4x + 4 = x + 82

4x - x = 82 - 4

3x = 78

x = 78/3

x = 26

Therefore, the three consecutive numbers are 26,27,28.