Twin primes are consecutive prime numbers whose difference is 2. for example (3,5) , (11,13) ,(17,19) are all twin primes . we define the distance of any twin prime pair from a positive integer as follows if (p1, p2) is a twin prime pair and n is a positive integer then the distance of the twin prime pair from n is :
minimum (abs(n-p1),abs return the whole value of it's argument and minimum returns the smaller of it's two argument.
WAP that reads in appositive integer n and prints out the twin prime pair that has the least distance from n. for example if n is 30 the pair is (29,31) ,if n is 13 it is (11,13), if n is 49 it is (41,43) if n is 54 it is (59,61)
sample data
inputs :give the number :34
outputs : number read in is :34 P1= 29 P2=31
input: give the number :60 P1=59 P2=61
PLEASE GIVE THE WHOLE PROGRAM I'LL MARK YOU AS BRAINLIST NO SPAM!!
Answers
Explanation:
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int i,j,k=30000;
int n,p2,p1,l;
int minimum(int,int);
int prime(int);
int abs(int);
cout<<"Enter a number : ";
cin>>n;
for(i=0;i<2*n;i++)
{
p1=prime(i);
p2=prime(i+2);
if (p1==0 || p2==0)
{
continue;
}
if(minimum(abs(n-p1),abs(n-p2))<k)
{
k=minimum(abs(n-p1),abs(n-p2));
j=p1;l=p2;
}
}
cout<<"\n twin prime nearest to "<<n<<"="<<j<<","<<l;
getch();
}
int abs(int n)
{
if(n<0)
return(-n);
else
return(n);
}
int minimum(int a,int b)
{
int n=(a<b)?a:b;
return(n);
}
int prime(int n)
{
int f=n;
for(int i=2;i<n-1;i++)
{
if(n%i==0)
{
f=0;
break;
}
}
return(f);
} public class ISC02Q1
{
private int prime(int n)
{
int f=n;
for(int i=2;i<n-1;i++)
{
if(n%i==0)
{
f=0;
break;
}
}
return(f);
}
private int abs(int n)
{
if(n<0)
return(-n);
else
return(n);
}
private int minimum(int a,int b)
{
int n=(a<b)?a:b;
return(n);
}
public void main(int n)
{
int i,j=0,k=30000;
int p2=0,p1=0,l=0;
for(i=0;i<2*n;i++)
{
p1=prime(i);
p2=prime(i+2);
if(p1==0 || p2==0)
{
continue;
}
if(minimum(abs(n-p1),abs(n-p2))<k)
{
k=minimum(abs(n-p1),abs(n-p2));
j=p1;
l=p2;
}
}
System.out.println("Twin prime nearest to "
+n+"="+j+","+l);
}
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