Question

Two 1.2 k resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is

Answer 1

1/R =1/3.3 +1/2.4
=(80+110)/264
then simplify

Answer 2

Answer:

Two 1.2k resistors are in series and this series and this series combination is in parallel with a 3.3 k resistor . The total resistance is 3.12k

Explanation:

In series R1=1.2k+1.2k

                  =2.4k

In parallel we know,1/R= 1/R1+1/R2

In parallel : 1/Rt ⇒1/R1+1/R2=1/2.4+1/3.3

                                            =.72

Total resistance =2.4k+.72k

                        =3.12k

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