Question

Two 20 kg sphere are placed with their centers 50cm apart. What is the. Magnitude of gravitational force each exerted on other.

Answer 1

Answer:

Explanation:

m1=m2=20kg

r=50cm=0.5m

F=G m1m2/r^2=6.67*10^-11*20*20/0.5^2=1.06*10^-7N

Answer 2

Answer:

$= > g = 1.07 \times {10}^{ - 19} \:$

Explanation:

Information provided by the question to us,

M = 20 kg

m = 20 kg

r = 50 cm = 50/100 m = 0.5 m

Also, we know that,

$G = 6.67 \times {10}^{ - 11}$

We know that,

$g = \frac{G \times M \times m}{ {r}^{2} }$

Hence, we have the required information and we will get our desired answer by substituting the values in the formula,

$g = \frac{6.67 \times {10}^{ - 19} \times 20 \times 20 }{ {(0.5)}^{2} } \\ \\ = > g = \frac{6.67 \times 400 \times {10}^{ - 19} }{0.25} \\ \\ = > g = \frac{667 \times 4 \times 10 {}^{ - 19} }{25 \times {10}^{ - 2} } \\ \\ = > g = \frac{2668 \times 10 {}^{ - 19 - ( - 2)} }{25} \\ \\ = > g = 106.72 \times {10}^{ - 17} \\ = > g = 1.0672 \times 10 {}^{ - 19}$

We can round off the result to two decimal places,

$= > g = 1.07 \times {10}^{ - 19}$