Question

Two 3 kg masses have velocities v1=2i+3j m/s and v2=4i-6j m/s. Find:
(a)Velocity of centre of mass.
(b)Total momentum of the system.
(c)The velocity of centre of mass at 5s after application of a constant force F=24i N.
(d) Position of centre of mass after 5s if it is at the origin at t=0.

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Answer 1

Answer:

Given that,

The velocities of both particles

  v1=2i^m/s

 v2=2j^m/s

 The acceleration of both particles

  a1=(3i^+3j^)m/s2

 a2=0

 Now, the center of mass

  vcom=m1+m2m1v1+m2v2

 vcom=2m2m(i^+j^)

 vcom=(i^+j^)m/s

 Now,

  acom=

Explanation:

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