Question

Two 400 mm diameter pulleys are keyed to a simply supported shaft 500 mm apart. Each pulley is 100
mm from its support and has horizontal belts, tension ratio being 2.5. If the shear stress is to be limited

to 80 MPa while transmitting 45 kW at 900 r.p.m., find the shaft diameter if it is to be used for the input-
output belts being on the same or opposite sides.

Answer 1

Answer:

The shaft diameter if it is to be used for the input-output belts being on the same or opposite sides is 40 mm

Explanation:

From the above question,

They have given :

Two 400 mm diameter pulleys are keyed to a simply supported shaft 500 mm apart. Each pulley is 100

mm from its support and has horizontal belts, tension ratio being 2.5. If the shear stress is to be limited mm from its support and has horizontal belts, tension ratio being 2.5. If the shear stress is to be limited to 80 MPa while transmitting 45 kW at 900 r.p.m.

P = (T1 – T2)V T1

P = Tension on the tight side,

T2 = Tension on the slack side,

V = velocity of the belt Calculation

Given: D = 400 mm = 0.4 m,

T1T2=1.2,

Maximum tension = 240 kN,

N = 60 rpm Since

Between T1 and T2, T1 is always greater than T2.

Therefore,

T1 = 240 kN,

T1T2 = 1.2

       = T2

       = 2401.2

       = 200 kN

V = πDN60

   = π × 0.2 × 6060

   = 0.628 m/s

Power transmitted by the pulley, P = (T1 – T2)V

                                                         = (240 - 200) × 0.628

                                                         = 25.12 kW

The shaft diameter if it is to be used for the input-output belts being on the same or opposite sides is 40 mm.

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