Question

two 4uf capacitors in series is equal to___
a. 8uF b. 4uF
c.2 uF d.6uF​

Answer 1

Answer:

c. 2 μF

Explanation:

1/Cs = 1/C₁ + 1/C₂

       = 1/4 + 1/4

       = 2/4

       = 1/2

Cs = 2μF

Answer 2

The value of net capacitance of two 4uf capacitors in series is 2uf (option c).

Given:

The two 4uf capacitors are in series.

To Find:

The value of net capacitance of two 4uf capacitors in series.

Solution:

We are required to find the value of net capacitance of two 4uf capacitors in series.

Net capacitance in series connection is given as

For n capacitors,

1/Ceff = 1/C₁+1/C₂+......+1/Cₙ

For 2 capacitors

1/Ceff = 1/C₁+1/C₂  ------(1)

C₁ = C₂ = 4uf

Both the capacitors have the same capacitance.

Substitute the values of C₁ and C₂ in equation(1)

1/Ceff = 1/4+1/4

1/Ceff = 2/4

Ceff = 4/2

Ceff = 2uf

Therefore, The value of net capacitance of two 4uf capacitors in series is 2uf (option c).

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