Question

Two 500w heaters when connected in series across a source of constant voltage V supply Q joules of heat in a certain time T. when the heater connected in parallel across the same source , the amount of heat energy supplied in the same time T will be

Answer 1

Answer :

Hence the amount energy supplied in the same time T is 4Q

Explanation :

Let the heat supplied be Q

Constant voltage be V

Let time be T  

According to question when the heater connected in parallel across the same source, the amount of heat energy supplied in the same time t will me  

Q= V^2/2R × T

Q2 = V^2/R/2 × T

= 2× V^2/R × T

= 2(2Q)

= 4Q

Hence the amount energy supplied in the same time T is 4Q