Math, asked by abijithchennai, 9 months ago

Two A.P’s have the same common difference. The first term of one of these is 8 and that of the other is 3. The difference between their 30th terms is

Answers

Answered by guideboy509
3

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A.P1 = -1,(-1+d).....

A.P2 = -8,(-8+d).....

a4 = a+3d

Difference between their 4th term ;

= (-8+3d)-(-1+3d)

= -8+3d+1-3d

= -8+1

= -7

______

Answered by adwaitjoshi28
4

Answer:

5

Step-by-step explanation:

nth term of an Arithmetic progression is given by :

, where a= First term and d= common difference.

Given : Two AP have the same common difference.

The first term of one of these is 3 and that of the other is 8.

Then, the nth term of two APs will be :

a=3+(n-1)d

b=8+(n-1)d

First term for both APs.

a2=3+d

b2=8+d

Difference between their  2nd terms=b2-a2=8+d-3-d=8-3=5

Similarly , 30thth terms

=5

Therefore the answer of all options is 5.

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