Question

Two A.P’s have the same common difference. The first term of one of these is 8 and that of the other is 3. The difference between their 38th terms is

Answer 1

Answer:

5

Step-by-step explanation:

a1 = 8

a2 = 3

d1 = x

d2 = x

T38 = a + (37) d

Difference between 38th terms = a1+37d - (a2+37d)

                                                     = a1-a2 +37d-37d

                                                     = a1-a2 = 8-3 = 5

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