Two A.P’s have the same common difference. The first term of one of these is 8 and that of the other is 3. The difference between their 38th terms is?
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Answer:
AP1
a=8 d= m
T38 = 8 +37 m
AP2
A=3 d= m
T38 = 3+ 37m
Difference = 8 +37m -3-37 m
=5
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