Question

Two absolute scales A and B have triple points of water defined to be 200 A and 300 B (given triple point of water is = 276.16 K). The relation between TA and TB is

Answer 1

$\huge\underline{\overline{\mid{\bold{\orange{Relation-}}\mid}}}$

acc. to question,

200A=350B

Given,

(triple point of water on scale A -200A.

Triple point of water on scale B=350B)

$200A=350B=273.16K \: or \:1A = \dfrac{273.16}{200}K$

and $1B= \frac{273.16}{350}K$

relation between $T_A\ and\ T_B$,

$\dfrac{T_A}{T_B} = \dfrac{200}{350}= \dfrac{4}{7}$

$T_A=\dfrac{4}{7}T_B$

Answer 2

200A=350B

Given,

(triple point of water on scale A -200A.

Triple point of water on scale B=350B)

200A=350B=273.16K \: or \:1A = \dfrac{273.16}{200}K200A=350B=273.16Kor1A=

200

273.16

K

and 1B= \frac{273.16}{350}K1B=

350

273.16

K

relation between T_A\ and\ T_BT

A

and T

B

,

\dfrac{T_A}{T_B} = \dfrac{200}{350}= \dfrac{4}{7}

T

B

T

A

=

350

200

=

7

4

T_A=\dfrac{4}{7}T_BT

A

=

7

4

T

B