Two adajcent angle of a prallagramare in equal ratio find the measure of the angle in the prallagrem
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What is the cosine of the obtuse angle formed from the intersection of the two medians drawn from the vertex of the acute angles of an isosceles right triangle? That's a mouthful but consider sketch below:
Median CD, which perpendicularly bisects AB, has a 2 to 1 ratio from CO to OD. We need to find angle AOB.
Tangent theta = 2/3 which means theta is 33.7 degrees. Angle DOB must be 90–33.7 = 56.3 deg.
Therefore angle AOB is 112.6 degrees.
Cosine 112.6 deg = -.384
Median CD, which perpendicularly bisects AB, has a 2 to 1 ratio from CO to OD. We need to find angle AOB.
Tangent theta = 2/3 which means theta is 33.7 degrees. Angle DOB must be 90–33.7 = 56.3 deg.
Therefore angle AOB is 112.6 degrees.
Cosine 112.6 deg = -.384
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