Question

two adjacent angle of 11gm are (3x-4)⁰ and (8x+16)⁰ find the value of x,and hence find the measure of each of it's angel is​

Answer 1

Step-by-step explanation:

Let ∠A = (3x-4)o and ∠B = (3x+16)o Let ∠A and ∠B are two adjacent angles. But we know that sum of adjacent angles of a parallelogram is 180o ∠A + ∠B = 180o (3x-4)o + (3x+16)o= 180o 6x + 12 = 180o 6x = 180o-12o 6x = 168o X= 168o/6 = 280 ∠A = (3x-4)o=3 × 28 – 4 = 80o ∠B = (3x+16)o= 3 × 28 + 16 = 100o Also ∠B + ∠C = 180o [Since ∠B and ∠C are adjacent angles] 100o+ ∠C = 180o ∠C = 180o– 100o= 80o. Now ∠C + ∠D = 180o [Since ∠C and ∠D are adjacent angles] 80o+ ∠D = 180o ∠D = 180o– 80o= 100oRead more on Sarthaks.com - https://www.sarthaks.com/738559/adjacent-angles-parallelogram-and-find-value-and-hence-find-the-measure-each-its-angle